The dimension of P = frac{B^2 l^2}{m} is,wher | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic force is given by $F = BIL$,where $B$ is the magnetic field,$I$ is the current,and $L$ is the length.Therefore,the dimension of $B$ i

Vedclass · Accepted Answer

$ML^2T^{-4}I^{-2}$

Vedclass · Answer

(B) The magnetic force is given by $F = BIL$,where $B$ is the magnetic field,$I$ is the current,and $L$ is the length.Therefore,the dimension of $B$ is $[B] = \frac{[F]}{[I][L]} = \frac{[MLT^{-2}]}{[I][L]} = [MT^{-2}I^{-1}]$.Now,substitute the dimensions into the expression for $P$:$[P] = \frac{[B]^2 [l]^2}{[m]} = \frac{[MT^{-2}I^{-1}]^2 [L]^2}{[M]}$.$[P] = \frac{[M^2 T^{-4} I^{-2}] [L^2]}{[M]}$.$[P] = [ML^2 T^{-4} I^{-2}]$.

The dimension of $P = \frac{B^2 l^2}{m}$ is,where $B = \text{magnetic field}$,$l = \text{length}$,$m = \text{mass}$.

Similar Questions

The dimensions of the interatomic force constant are

Give the dimensional formula of surface tension.

Dimensions of which pair are the same? Identify the pair.

Out of the following four dimensional quantities,which one is called a dimensional constant?

Which two of the following five physical parameters have the same dimensions?
$(a)$ Energy density
$(b)$ Refractive index
$(c)$ Dielectric constant
$(d)$ Young's modulus
$(e)$ Magnetic field

Vedclass Test Series

Exam Paper Generator

Online Exam Module